C program to find the Armstrong Number between intervals

A  number of n digit is called Armstrong number if sum of the power of n of its digits is equal to the number itself.
For example a number of three digits integer is an Armstrong number if the sum of the cubes of its digits is equal to the number itself. 153 is an Armstrong number since 1*1*1 + 5*5*5 + 3*3*3 = 371. 

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PROBLEM STATEMENT

Write a program in C to find the Armstrong Number between intervals.

SOURCE CODE

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#include #include int main() { int a, b, i, num1, num2, rem, n = 0, result = 0; printf("Enter the first interval: "); scanf("%d", &a); printf("Enter the last interval: "); scanf("%d", &b); printf("Armstrong numbers between %d and %d are: ", a, b); for(i = a + 1; i <= b; i++) { num1 = i; num2 = i; //checking number of digits while (num1 != 0) { num1 = num1 / 10; n++; } while (num2 != 0) { rem = num2 % 10; result = result + pow(rem, n); num2 = num2 / 10; } if (result == i) { printf("%d ", i); } n = 0; // setting n as o for next iteration result = 0; } return 0; }

OUTPUT

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